HW 3 Help ˆ ˆ ˆ. From Newton s second law, the acceleration of the toy rocket is [Eq. 2] ˆ ˆ. net
|
|
- Chloe Hunt
- 5 years ago
- Views:
Transcription
1 HW 3 Help 3. ORGANIZE AND PLAN We can use Newton s second law to find the acceleration of the rocet. The force on the rocet will be the vector sum of all the forces acting on it, which are the force due to gravity (straight down) and the force from the rocet engine (straight up). We will use a coordinate system where ĵ represents the upward vertical direction. Known: m = 3.5 g; F engine = 95.3 N ˆj SOLVE The force acting on the rocet is [Eq. ] F =F +mg= 95.3 N j 3.5 g 9.8 m/s ( j ) = 6 N j. engine ˆ ˆ ˆ From Newton s second law, the acceleration of the toy rocet is [Eq. ] a=f / m= 6 N j /3.5 g = 7.4 m/s j. ˆ REFLECT The rocet is accelerating upward at almost twice the acceleration due to gravity. This is a significant acceleration, compared to what we experience on a daily basis. To appreciate the acceleration due to gravity, try to catch a stic that falls from a stationary position, with your hand initially positioned above the stic. It can be done, but it s not easy. Imagine now the rocet accelerating at almost twice that rate ˆ 35.ORGANIZE AND PLAN vector form, F=ma. This problem involves the application of Newton s second law in Known: m = 00 g = 0. g; a 0.55 m/s i ˆ m/s ˆj SOLVE Inserting the nown quantities (with the correct units) into Newton s second law, we have [Eq. ] ˆ ˆ ˆ ˆ F ma 0. g 0.55 m/s i m/s j N i N j This is the force needed to generate the desired acceleration. The direction of this force is [Eq. ] atan 68.6, From Eq. () we now the force vector is in the second quadrant, so we the direction of the force must be.4 above the horizontal. The magnitude of the force is [Eq. 3] F 0.55 N N N REFLECT Note that we had to convert the mass from grams to ilograms so that the result of our calculation would be in SI units (i.e., Newtons).
2 The crane supplies an upward force on the beam, and gravity supplies a downward force. The force will be the vector sum of the two. Once we find the force, we can use Newton s second law to find the acceleration of the beam. We chose a coordinate system for this problem in which ĵ is oriented vertically upward. Known: m = 85 g; F 960 N ˆj ; g 9.8 m /s ˆ j 44.ORGANIZE AND PLAN crane SOLVE The force is the vector sum of all the forces on the beam, which in this case is gravity and the force applied by the crane [Eq. ]: F F mg 960 N j (85 g)(9.8 m/s ) j 47 N j crane ˆ ˆ ˆ We insert this result into Newton s second law to find the acceleration of the beam [Eq. ]: F ma, a F / m j0.8 m/s j (85 g) (47 N) ˆ ˆ REFLECT Most of the force applied by the crane is used to overcome gravity. If the force (i.e., crane + gravity) is applied to the beam for sec, the beam will gain a speed of 0.8 m/s in the upward direction. How much force must the crane now exert to maintain this speed constant? Simply enough to mae F. From Eq. this is F mg. 0 crane Mae a drawing of the situation on which all the forces for each case are drawn. Sum up the forces and use Newton s second law to find the normal force in each case. 46.ORGANIZE AND PLAN N N 5 N N N N mg mg mg 5 N N (a) (b) (c) Known: m =.5 g SOLVE From Newton s second law it is nown that, since the boo is stationary, the force must be zero. From the figure above, the force for case (a) is [Eq. ] Thus the normal is N( ˆj ). F 0 nmg j n mg j j j ˆ ˆ (.5 g)(9.8 m/s ) ˆ Nˆ
3 Repeating the same calculation for case (b) gives [Eq. ] F 0 nmg j 5 N j n mg j j j j j ˆ ˆ ˆ 5 N ˆ N ˆ 5 N ˆ 7 N ˆ Thus the normal force applied by the table on the boo has been reduced to For case (c), we have [Eq. 3] F 0 nmg j 5 N j n mg j j j j j ˆ ˆ ˆ 5 N ˆ N ˆ 5 N ˆ 37 N ˆ ˆ 7 ( ). N j Thus, when you push down on the boo with 5 N of force, the table must now supply a force of 37 N( ˆj ) on the boo. REFLECT What is the normal force supplied by the floor on each of the 4 table legs for each situation, if we assume the boo is positioned at the center of the table? You can find this by doing the same calculations, but replacing the mass m by the mass of the table plus the boo. Also, don t forget that the floor is pushing up on all 4 legs equally, so the force applied on each leg will be ¼ of the total normal force. This problem involves a frictionless pulley and a presumably massless wire, so the force applied by the wire on each hanging bloc is the same. In addition, the acceleration of m will be of equal magnitude but antiparallel to the acceleration of m [Eq. ]: a a. Known: m m SOLVE (a) The force diagram is shown in the figure below. 6.ORGANIZE AND PLAN T T N m m m g m g (b) Using Newton s second law, the acceleration on m is [Eq. ] and on m it is [Eq. 3] F ma T mg ma Tmg j 3 ˆ F ma T mg ma Tmg j Using Eqs. and 3 to express a and T in terms of the other variables in Eq., we get [Eq. 4] ˆ
4 From Eq. [Eq. 5], (c) If 0.50 g ˆ ma m mg ˆ m mg ˆ m m m ma ma mgmg j a j j m m g a m m m and m, then [Eq. 6] 0.00 g a.40 m/s a.40 m/s ˆj ˆj ˆj REFLECT Consider what would happen if m 0. In this case, m would accelerate down with the acceleration due to gravity, and m would accelerate upward with the same rate. The opposite would be true if m 0. Since the tightrope-waler does not accelerate, the force on her must be zero (Newton s second law). Known: m 63 g; 9.5 SOLVE (a) The force diagram is shown in the figure below. 68.ORGANIZE AND PLAN N u u T T (b) Summing the forces in the vertical direction, we have [Eq. ] F 0mgTsin ˆj mg 63 g9.8 m/s ˆj T sin9.5 T 870 N REFLECT The horizontal component of the rope tension is T cos 845 N, and the vertical component is T sin 309 N. 4
5 7.ORGANIZE AND PLAN Using Eq. 4.6, the magnitude of the iic friction force is [Eq. ] f n. The friction force will act to oppose the velocity, which we assume is in the î direction. Therefore [Eq. ], ˆ find the acceleration, and then the distance traveled. Known: = 0.03; x x 6 m iˆ ; v 0 m/ s; 0 f mg i. From this and Newton s second law we can f 0 0 ˆ v v i SOLVE Using Newton s second law and Eq., the acceleration of the puc is [Eq. 3] F f ma ˆ m/s ˆ 0.3 m/s ˆ mg a i i i m (b) To find the distance traveled before stopping, we use [Eq. 4] vf v0 at and [Eq. 5] x x v t at to find [Eq. 6] f 0 0 / v0 v0 xf x0 v0 /a a a v x x a i 6 m 0.3 m/s i 4.0 m/s i ˆ ˆ ˆ 4.0 m/si. 0 f 0 Thus, the puc s initial velocity must be REFLECT Notice that we have to be careful with the direction of the vector quantities in Eq. 6 to ensure the correct result. We can use the same force diagram as for Problem 75. If the car is moving down the incline at a constant speed, then by Newton s second law there is no force on the car. Known:.4 ; a 0 m/s SOLVE Using Newton s second law and Eq. 4.6, we get [Eq. ] 76.ORGANIZE AND PLAN F f mg i ma ˆ sin ˆ sinˆ0 ˆ ˆ n i mg i mgcos i mgsin i 0 tan 0.04 REFLECT This coefficient of iic friction is between that of the wooden bloc (0.87, Problem 75) and that of the stone on ice (0.04, Problem 73). 5
6 94. ORGANIZE AND PLAN The horizontal force on the car generates the centripetal acceleration (see Eq. 4.9). Known: F 790 N i ˆ ; R 0 m; v.5 m/s ˆ SOLVE r (a) See the force diagram below. Car N v F r R cos(u) View from above R =. m N F r u mg View from in front of car There are two diagrams, the upper one is the view from above the car, the lower one is the view from in front of the car. (b) Using Eq. 4.9, we find the mass of the car is [Eq. ] mv Fr R FR 790 N 0 m r m 54 g v.5 m/s REFLECT Notice that the units cancel properly in Eq.. 6
7 09.ORGANIZE AND PLAN Use the inematic equations (see, e.g., Problem 4, Eq. 3) to calculate the acceleration. Use Newton s second law to calculate the force due to iic friction from the acceleration. Known: m.90 g; xx0 3.5 m; v0.0 m/s SOLVE From, e.g., Problem 4, Eq. 3, we calculate the magnitude of the acceleration [Eq. ]. v.0 m/s 0 a m/s x x0 3.5 m Using Newton s second law and Eq. 4.6, we can find the coefficient of iic friction [Eq. ]. F ma n ma mg ma m/s a/ g m/s REFLECT The attentive reader might have noticed a sign difference between Eq. 3, Problem 4, and Eq. of this problem. The difference is that the former is a vector equation, while the later relationship is scalar. Since the acceleration in this problem is due to the iic friction force, the direction of the acceleration vector must be antiparallel to the velocity vector. 7
PHYSICS 231 Laws of motion PHY 231
PHYSICS 231 Laws of motion 1 Newton s Laws First Law: If the net force exerted on an object is zero the object continues in its original state of motion; if it was at rest, it remains at rest. If it was
More informationPHYSICS 221, FALL 2009 EXAM #1 SOLUTIONS WEDNESDAY, SEPTEMBER 30, 2009
PHYSICS 221, FALL 2009 EXAM #1 SOLUTIONS WEDNESDAY, SEPTEMBER 30, 2009 Note: The unit vectors in the +x, +y, and +z directions of a right-handed Cartesian coordinate system are î, ĵ, and ˆk, respectively.
More informationUNIT-07. Newton s Three Laws of Motion
1. Learning Objectives: UNIT-07 Newton s Three Laws of Motion 1. Understand the three laws of motion, their proper areas of applicability and especially the difference between the statements of the first
More informationMASSACHUSETTS INSTITUTE OF TECHNOLOGY Department of Physics. Physics 8.01 Fall Problem Set 2: Applications of Newton s Second Law Solutions
MASSACHUSETTS INSTITUTE OF TECHNOLOGY Department of Physics Physics 8.01 Fall 2012 Problem 1 Problem Set 2: Applications of Newton s Second Law Solutions (a) The static friction force f s can have a magnitude
More informationConcept of Force Challenge Problem Solutions
Concept of Force Challenge Problem Solutions Problem 1: Force Applied to Two Blocks Two blocks sitting on a frictionless table are pushed from the left by a horizontal force F, as shown below. a) Draw
More informationQ16.: A 5.0 kg block is lowered with a downward acceleration of 2.8 m/s 2 by means of a rope. The force of the block on the rope is:(35 N, down)
Old Exam Question Ch. 5 T072 Q13.Two blocks of mass m 1 = 24.0 kg and m 2, respectively, are connected by a light string that passes over a massless pulley as shown in Fig. 2. If the tension in the string
More informationIsaac Newton ( ) 1687 Published Principia Invented Calculus 3 Laws of Motion Universal Law of Gravity
Isaac Newton (1642-1727) 1687 Published Principia Invented Calculus 3 Laws of Motion Universal Law of Gravity Newton s First Law (Law of Inertia) An object will remain at rest or in a constant state of
More information= M. L 2. T 3. = = cm 3
Phys101 First Major-1 Zero Version Sunday, March 03, 013 Page: 1 Q1. Work is defined as the scalar product of force and displacement. Power is defined as the rate of change of work with time. The dimension
More informationPhys 1401: General Physics I
1. (0 Points) What course is this? a. PHYS 1401 b. PHYS 1402 c. PHYS 2425 d. PHYS 2426 2. (0 Points) Which exam is this? a. Exam 1 b. Exam 2 c. Final Exam 3. (0 Points) What version of the exam is this?
More informationPH211 Chapter 4 Solutions
PH211 Chapter 4 Solutions 4.3.IDENTIFY: We know the resultant of two vectors of equal magnitude and want to find their magnitudes. They make the same angle with the vertical. Figure 4.3 SET UP: Take to
More informationy(t) = y 0 t! 1 2 gt 2. With y(t final ) = 0, we can solve this for v 0 : v 0 A ĵ. With A! ĵ =!2 and A! = (2) 2 + (!
1. The angle between the vector! A = 3î! 2 ĵ! 5 ˆk and the positive y axis, in degrees, is closest to: A) 19 B) 71 C) 90 D) 109 E) 161 The dot product between the vector! A = 3î! 2 ĵ! 5 ˆk and the unit
More informationPhys101 First Major-111 Zero Version Monday, October 17, 2011 Page: 1
Monday, October 17, 011 Page: 1 Q1. 1 b The speed-time relation of a moving particle is given by: v = at +, where v is the speed, t t + c is the time and a, b, c are constants. The dimensional formulae
More informationLecture 5. Dynamics. Forces: Newton s First and Second
Lecture 5 Dynamics. Forces: Newton s First and Second What is a force? It s a pull or a push: F F Force is a quantitative description of the interaction between two physical bodies that causes them to
More informationYou may use g = 10 m/s 2, sin 60 = 0.87, and cos 60 = 0.50.
1. A child pulls a 15kg sled containing a 5kg dog along a straight path on a horizontal surface. He exerts a force of a 55N on the sled at an angle of 20º above the horizontal. The coefficient of friction
More information2. If a net horizontal force of 175 N is applied to a bike whose mass is 43 kg what acceleration is produced?
Chapter Problems Newton s 2nd Law: Class Work 1. A 0.40 kg toy car moves at constant acceleration of 2.3 m/s 2. Determine the net applied force that is responsible for that acceleration. 2. If a net horizontal
More informationNewton s 3 Laws of Motion
Newton s 3 Laws of Motion 1. If F = 0 No change in motion 2. = ma Change in motion Fnet 3. F = F 1 on 2 2 on 1 Newton s First Law (Law of Inertia) An object will remain at rest or in a constant state of
More informationChap. 4: Newton s Law of Motion
Chap. 4: Newton s Law of Motion And Chap.5 Applying Newton s Laws (more examples) Force; Newton s 3 Laws; Mass and Weight Free-body Diagram (1D) Free-body Diagram (1D, 2 Bodies) Free-body Diagram (2D)
More informationChapter 4. Forces and Mass. Classical Mechanics. Forces. Newton s First Law. Fundamental (Field) Forces. Contact and Field Forces
Chapter 4 Classical Mechanics Forces and Mass does not apply for very tiny objects (< atomic sizes) objects moving near the speed of light Newton s First Law Forces If the net force!f exerted on an object
More informationPhys 1401: General Physics I
1. (0 Points) What course is this? a. PHYS 1401 b. PHYS 1402 c. PHYS 2425 d. PHYS 2426 2. (0 Points) Which exam is this? a. Exam 1 b. Exam 2 c. Final Exam 3. (0 Points) What version of the exam is this?
More informationCHAPTER 4 TEST REVIEW -- Answer Key
AP PHYSICS Name: Period: Date: DEVIL PHYSICS BADDEST CLASS ON CAMPUS 50 Multiple Choice 45 Single Response 5 Multi-Response Free Response 3 Short Free Response 2 Long Free Response AP EXAM CHAPTER TEST
More informationRandom sample problems
UNIVERSITY OF ALABAMA Department of Physics and Astronomy PH 125 / LeClair Spring 2009 Random sample problems 1. The position of a particle in meters can be described by x = 10t 2.5t 2, where t is in seconds.
More informationWork and Energy (Work Done by a Constant Force)
Lecture 11 Chapter 7 Physics I 10.16.2013 Work and Energy (Work Done by a Constant Force) Course website: http://faculty.uml.edu/andriy_danylov/teaching/physicsi Lecture Capture: http://echo360.uml.edu/danylov2013/physics1fall.html
More informationChapter 4. Dynamics: Newton s Laws of Motion. That is, describing why objects move
Chapter 4 Dynamics: Newton s Laws of Motion That is, describing why objects move orces Newton s 1 st Law Newton s 2 nd Law Newton s 3 rd Law Examples of orces: Weight, Normal orce, Tension, riction ree-body
More informationExam 1 Solutions. PHY 2048 Spring 2014 Acosta, Rinzler. Note that there are several variations of some problems, indicated by choices in parentheses.
Exam 1 Solutions Note that there are several variations of some problems, indicated by choices in parentheses. Problem 1 Let vector a! = 4î + 3 ĵ and vector b! = î + 2 ĵ (or b! = î + 4 ĵ ). What is the
More informationChapter 4. Forces and Newton s Laws of Motion. continued
Chapter 4 Forces and Newton s Laws of Motion continued Quiz 3 4.7 The Gravitational Force Newton s Law of Universal Gravitation Every particle in the universe exerts an attractive force on every other
More informationMULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.
Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) A baseball is thrown vertically upward and feels no air resistance. As it is rising A) both
More informationWebreview practice test. Forces (again)
Please do not write on test. ID A Webreview 4.3 - practice test. Forces (again) Multiple Choice Identify the choice that best completes the statement or answers the question. 1. A 5.0-kg mass is suspended
More informationTwo Hanging Masses. ) by considering just the forces that act on it. Use Newton's 2nd law while
Student View Summary View Diagnostics View Print View with Answers Edit Assignment Settings per Student Exam 2 - Forces [ Print ] Due: 11:59pm on Tuesday, November 1, 2011 Note: To underst how points are
More information1. Draw a FBD of the toy plane if it is suspended from a string while you hold the string and move across the room at a constant velocity.
1. Draw a FBD of the toy plane if it is suspended from a string while you hold the string and move across the room at a constant velocity. 2. A 15 kg bag of bananas hangs from a taunt line strung between
More informationChapter 4: Newton s Second Law F = m a. F = m a (4.2)
Lecture 7: Newton s Laws and Their Applications 1 Chapter 4: Newton s Second Law F = m a First Law: The Law of Inertia An object at rest will remain at rest unless, until acted upon by an external force.
More informationA. B. C. D. E. v x. ΣF x
Q4.3 The graph to the right shows the velocity of an object as a function of time. Which of the graphs below best shows the net force versus time for this object? 0 v x t ΣF x ΣF x ΣF x ΣF x ΣF x 0 t 0
More informationPhys101 Second Major-162 Zero Version Coordinator: Dr. Kunwar S. Saturday, March 25, 2017 Page: 1
Coordinator: Dr. Kunwar S. Saturday, March 25, 2017 Page: 1 Q1. Only two horizontal forces act on a 3.0 kg body that can move over a frictionless floor. One force is 20 N, acting due east, and the other
More informationPhysics B Newton s Laws AP Review Packet
Force A force is a push or pull on an object. Forces cause an object to accelerate To speed up To slow down To change direction Unit: Newton (SI system) Newton s First Law The Law of Inertia. A body in
More informationAP Physics 1 Multiple Choice Questions - Chapter 4
1 Which of ewton's Three Laws of Motion is best expressed by the equation F=ma? a ewton's First Law b ewton's Second Law c ewton's Third Law d one of the above 4.1 2 A person is running on a track. Which
More informationReading Quiz. Chapter 5. Physics 111, Concordia College
Reading Quiz Chapter 5 1. The coefficient of static friction is A. smaller than the coefficient of kinetic friction. B. equal to the coefficient of kinetic friction. C. larger than the coefficient of kinetic
More informationChapter 5. Force and Motion I
Chapter 5 Force and Motion I 5 Force and Motion I 25 October 2018 PHY101 Physics I Dr.Cem Özdoğan 2 3 5-2 Newtonian Mechanics A force is a push or pull acting on a object and causes acceleration. Mechanics
More informationPhys101 Second Major-162 Zero Version Coordinator: Dr. Kunwar S. Saturday, March 25, 2017 Page: N Ans:
Coordinator: Dr. Kunwar S. Saturday, March 25, 2017 Page: 1 Q1. Only two horizontal forces act on a 3.0 kg body that can move over a frictionless floor. One force is 20 N, acting due east, and the other
More informationFrictional Force ( ): The force that occurs when two object rub against one another and always OPPOSES motion. It's not dependent on area of contact.
Force Push or pull Law Scientific theory that has been proven for many years (can be changed) Newton's 1 st Law (Law of Inertia): Object at rest stays at rest while an object in motion continues in motion
More informationExample force problems
PH 105 / LeClair Fall 2015 Example force problems 1. An advertisement claims that a particular automobile can stop on a dime. What net force would actually be necessary to stop a 850 kg automobile traveling
More informationChapter 4. Forces and Newton s Laws of Motion. continued
Chapter 4 Forces and Newton s Laws of Motion continued 4.9 Static and Kinetic Frictional Forces When an object is in contact with a surface forces can act on the objects. The component of this force acting
More informationPhys 201A. Homework 8 Solutions
Phys 01A Homewor 8 Solutions 15. (b) The static frictional force that blocs A and B eert on each other has a magnitude f. The force that B eerts on A is directed to the right (the positive direction),
More informationFriction forces. Lecture 8. Chapter 6. Physics I. Course website:
Lecture 8 Physics I Chapter 6 Friction forces Course website: http://faculty.uml.edu/andriy_danylov/teaching/physicsi Today we are going to discuss: Chapter 6: Some leftover (Ch.5) Kinetic/Static Friction:
More informationApplying Newton s Laws
Chapter 5 Applying Newton s Laws PowerPoint Lectures for University Physics, Twelfth Edition Hugh D. Young and Roger A. Freedman Lectures by James Pazun Goals for Chapter 5 To use and apply Newton s Laws
More informationFORCE AND NEWTON S LAWS OF MOTION
FORCE AND NEWTON S LAWS OF MOTION 4. ORGANIZE AND PLAN In what ways would a more massive gol ball change its light? We need to thin o what orces will act on the gol ball, and how the ball s light will
More information= y(x, t) =A cos (!t + kx)
A harmonic wave propagates horizontally along a taut string of length L = 8.0 m and mass M = 0.23 kg. The vertical displacement of the string along its length is given by y(x, t) = 0. m cos(.5 t + 0.8
More informationQuestion 01. A. Incorrect! This is not Newton s second law.
College Physics - Problem Drill 06: Newton s Laws of Motion Question No. 1 of 10 1. Which of the options best describes the statement: Every object continues in a state of rest or uniform motion in a straight
More informationChapter 4 DYNAMICS: FORCE AND NEWTON S LAWS OF MOTION
Chapter 4 DYNAMICS: FORCE AND NEWTON S LAWS OF MOTION Part (a) shows an overhead view of two ice skaters pushing on a third. Forces are vectors and add like other vectors, so the total force on the third
More informationSolved Problems. 3.3 The object in Fig. 3-1(a) weighs 50 N and is supported by a cord. Find the tension in the cord.
30 NEWTON'S LAWS [CHAP. 3 Solved Problems 3.1 Find the weight on Earth of a body whose mass is (a) 3.00 kg, (b) 200 g. The general relation between mass m and weight F W is F W ˆ mg. In this relation,
More information(35+70) 35 g (m 1+m 2)a=m1g a = 35 a= =3.27 g 105
Coordinator: Dr. W. L-Basheer Monday, March 16, 2015 Page: 1 Q1. 70 N block and a 35 N block are connected by a massless inextendable string which is wrapped over a frictionless pulley as shown in Figure
More informationPart A Atwood Machines Please try this link:
LAST NAME FIRST NAME DATE Assignment 2 Inclined Planes, Pulleys and Accelerating Fluids Problems 83, 108 & 109 (and some handouts) Part A Atwood Machines Please try this link: http://www.wiley.com/college/halliday/0470469080/simulations/sim20/sim20.html
More informationPhysics 2211 M Quiz #2 Solutions Summer 2017
Physics 2211 M Quiz #2 Solutions Summer 2017 I. (16 points) A block with mass m = 10.0 kg is on a plane inclined θ = 30.0 to the horizontal, as shown. A balloon is attached to the block to exert a constant
More informationPhysics 101 Lecture 5 Newton`s Laws
Physics 101 Lecture 5 Newton`s Laws Dr. Ali ÖVGÜN EMU Physics Department The Laws of Motion q Newton s first law q Force q Mass q Newton s second law q Newton s third law qfrictional forces q Examples
More informationPHYSICS 221, FALL 2010 EXAM #1 Solutions WEDNESDAY, SEPTEMBER 29, 2010
PHYSICS 1, FALL 010 EXAM 1 Solutions WEDNESDAY, SEPTEMBER 9, 010 Note: The unit vectors in the +x, +y, and +z directions of a right-handed Cartesian coordinate system are î, ĵ, and ˆk, respectively. In
More informationMOMENTUM, IMPULSE & MOMENTS
the Further Mathematics network www.fmnetwork.org.uk V 07 1 3 REVISION SHEET MECHANICS 1 MOMENTUM, IMPULSE & MOMENTS The main ideas are AQA Momentum If an object of mass m has velocity v, then the momentum
More informationChapters 5-6. Dynamics: Forces and Newton s Laws of Motion. Applications
Chapters 5-6 Dynamics: orces and Newton s Laws of Motion. Applications That is, describing why objects move orces Newton s 1 st Law Newton s 2 nd Law Newton s 3 rd Law Examples of orces: Weight, Normal,
More informationPractice. Newton s 3 Laws of Motion. Recall. Forces a push or pull acting on an object; a vector quantity measured in Newtons (kg m/s²)
Practice A car starts from rest and travels upwards along a straight road inclined at an angle of 5 from the horizontal. The length of the road is 450 m and the mass of the car is 800 kg. The speed of
More informationPhys101-T121-First Major Exam Zero Version, choice A is the correct answer
Phys101-T121-First Major Exam Zero Version, choice A is the correct answer Q1. Find the mass of a solid cylinder of copper with a radius of 5.00 cm and a height of 10.0 inches if the density of copper
More information24/06/13 Forces ( F.Robilliard) 1
R Fr F W 24/06/13 Forces ( F.Robilliard) 1 Mass: So far, in our studies of mechanics, we have considered the motion of idealised particles moving geometrically through space. Why a particular particle
More informationNewton s First Law and IRFs
Goals: Physics 207, Lecture 6, Sept. 22 Recognize different types of forces and know how they act on an object in a particle representation Identify forces and draw a Free Body Diagram Solve 1D and 2D
More informationB C = B 2 + C 2 2BC cosθ = (5.6)(4.8)cos79 = ) The components of vectors B and C are given as follows: B x. = 6.
1) The components of vectors B and C are given as follows: B x = 6.1 C x = 9.8 B y = 5.8 C y = +4.6 The angle between vectors B and C, in degrees, is closest to: A) 162 B) 111 C) 69 D) 18 E) 80 B C = (
More informationChapter 4 Force and Motion
Chapter 4 Force and Motion Units of Chapter 4 The Concepts of Force and Net Force Inertia and Newton s First Law of Motion Newton s Second Law of Motion Newton s Third Law of Motion More on Newton s Laws:
More informationUnits. EMU Physics Department. Ali ÖVGÜN.
Units Ali ÖVGÜN EMU Physics Department www.aovgun.com 1 mile = 1609 m January 22-25, 2013 January 22-25, 2013 Vectors Ali ÖVGÜN EMU Physics Department www.aovgun.com Example 1: Operations with Vectors
More informationPHYS 101 Previous Exam Problems. Kinetic Energy and
PHYS 101 Previous Exam Problems CHAPTER 7 Kinetic Energy and Work Kinetic energy Work Work-energy theorem Gravitational work Work of spring forces Power 1. A single force acts on a 5.0-kg object in such
More informationChapter 5. Force and Motion-I
Chapter 5 Force and Motion-I 5.3 Newton s First Law Newton s First Law: If no force acts on a body, the body s velocity cannot change The purpose of Newton s First Law is to introduce the special frames
More information1. A sphere with a radius of 1.7 cm has a volume of: A) m 3 B) m 3 C) m 3 D) 0.11 m 3 E) 21 m 3
1. A sphere with a radius of 1.7 cm has a volume of: A) 2.1 10 5 m 3 B) 9.1 10 4 m 3 C) 3.6 10 3 m 3 D) 0.11 m 3 E) 21 m 3 2. A 25-N crate slides down a frictionless incline that is 25 above the horizontal.
More informationLecture III. Introduction to Mechanics, Heat, and Sound /FIC 318
Introduction to Mechanics, Heat, and Sound /FIC 318 Lecture III Motion in two dimensions projectile motion The Laws of Motion Forces, Newton s first law Inertia, Newton s second law Newton s third law
More informationDynamics; Newton s Laws of Motion
Dynamics; Newton s Laws of Motion Force A force is any kind of push or pull on an object. An object at rest needs a force to get it moving; a moving object needs a force to change its velocity. The magnitude
More informationA force is a push or a pull.
A force is a push or a pull. Contact forces arise from physical contact. Action at adistance forces do not require contact and include gravity and electrical forces. 1 Force is a vector [F]=[Newton]=[N]
More informationPhysics 1 Second Midterm Exam (AM) 2/25/2010
Physics Second Midterm Eam (AM) /5/00. (This problem is worth 40 points.) A roller coaster car of m travels around a vertical loop of radius R. There is no friction and no air resistance. At the top of
More informationForces. Isaac Newton stated 3 laws that deal with forces and describe motion. Backbone of Physics
FORCES Forces Isaac Newton stated 3 laws that deal with forces and describe motion. Backbone of Physics Inertia Tendency of an object to remain in the same state of motion. Resists a change in motion.
More informationThe Concept of Force Newton s First Law and Inertial Frames Mass Newton s Second Law The Gravitational Force and Weight Newton s Third Law Analysis
The Laws of Motion The Concept of Force Newton s First Law and Inertial Frames Mass Newton s Second Law The Gravitational Force and Weight Newton s Third Law Analysis Models using Newton s Second Law Forces
More informationMULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.
PH 105 Exam 2 VERSION A Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) Is it possible for a system to have negative potential energy? A)
More informationMULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.
FLEX Physical Science AP Physics C Newton's Laws --- Conceptual Questions MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) You swing a bat and hit
More informationSolution of HW4. and m 2
Solution of HW4 9. REASONING AND SOLUION he magnitude of the gravitational force between any two of the particles is given by Newton's law of universal gravitation: F = Gm 1 m / r where m 1 and m are the
More informationPHYS 101 Previous Exam Problems. Force & Motion I
PHYS 101 Previous Exam Problems CHAPTER 5 Force & Motion I Newton s Laws Vertical motion Horizontal motion Mixed forces Contact forces Inclines General problems 1. A 5.0-kg block is lowered with a downward
More informationMULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.
PH 105 Exam 2 VERSION B Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) A boy throws a rock with an initial velocity of 2.15 m/s at 30.0 above
More informationAP Physics 1 First Semester Final Exam Review
AP Physics First Semester Final Exam Review Chapters and. Know the SI Units base units.. Be able to use the factor-label method to convert from one unit to another (ex: cm/s to m/year) 3. Be able to identify
More informationNewton s Laws.
Newton s Laws http://mathsforeurope.digibel.be/images Forces and Equilibrium If the net force on a body is zero, it is in equilibrium. dynamic equilibrium: moving relative to us static equilibrium: appears
More informationHelp Desk: 9:00-5:00 Monday-Thursday, 9:00-noon Friday, in the lobby of MPHY.
Help Desk: 9:00-5:00 Monday-Thursday, 9:00-noon Friday, in the lobby of MPHY. SI (Supplemental Instructor): Thomas Leyden (thomasleyden@tamu.edu) 7:00-8:00pm, Sunday/Tuesday/Thursday, MPHY 333 Chapter
More informationChapter Four Holt Physics. Forces and the Laws of Motion
Chapter Four Holt Physics Forces and the Laws of Motion Physics Force and the study of dynamics 1.Forces - a. Force - a push or a pull. It can change the motion of an object; start or stop movement; and,
More informationBe on time Switch off mobile phones. Put away laptops. Being present = Participating actively
A couple of house rules Be on time Switch off mobile phones Put away laptops Being present = Participating actively http://www.phys.tue.nl/nfcmr/natuur/collegenatuur.html Chapter 4 Newton s Laws of Motion
More informationProf. Dr. I. Nasser T171 Chapter5_I 12/10/2017
Prof. Dr. I. Nasser T171 Chapter5_I 1/10/017 Chapter 5 Force and Motion I 5-1 NEWTON S FIRST AND SECOND LAWS Newton s Three Laws Newton s 3 laws define some of the most fundamental things in physics including:
More informationProblem Set III Solutions
Problem Set III Solutions. The bloc is at rest which means that F x = F y = 0. From Figure, it is clear that F x = ma x = 0 = T cos a = T cos b () F y = ma y = 0 = T sin a + T sin b = mg. () Solving Equation
More informationFigure 5.1a, b IDENTIFY: Apply to the car. EXECUTE: gives.. EVALUATE: The force required is less than the weight of the car by the factor.
51 IDENTIFY: for each object Apply to each weight and to the pulley SET UP: Take upward The pulley has negligible mass Let be the tension in the rope and let be the tension in the chain EXECUTE: (a) The
More informationMain points of today s lecture: Normal force Newton s 3 d Law Frictional forces: kinetic friction: static friction Examples. Physic 231 Lecture 9
Main points of today s lecture: Normal force Newton s 3 d Law Frictional forces: kinetic friction: static friction Examples. Physic 3 Lecture 9 f N k = µ k f N s < µ s Atwood s machine Consider the Atwood
More informationPhysics 8 Wednesday, October 11, 2017
Physics 8 Wednesday, October 11, 2017 HW5 due Friday. It s really Friday this week! Homework study/help sessions (optional): Bill will be in DRL 2C6 Wednesdays from 4 6pm (today). Grace will be in DRL
More informationForces and Newton s Laws Notes
Forces and Newton s Laws Notes Force An action exerted on an object which can change the motion of the object. The SI unit for force is the Newton (N) o N = (kg m)/s 2 o Pound is also a measure of force
More informationCHAPTER 4 NEWTON S LAWS OF MOTION
62 CHAPTER 4 NEWTON S LAWS O MOTION CHAPTER 4 NEWTON S LAWS O MOTION 63 Up to now we have described the motion of particles using quantities like displacement, velocity and acceleration. These quantities
More informationQuestion 1. G.M. Paily Phys 211
Question 1 A 0.5 kg hockey puck slides along the surface of the ice with a speed of 10 m s. What force must be acting on the puck to keep it moving at constant velocity? A 0.05 N B 5 N C 20 N D 50 N E
More informationEQUATIONS OF MOTION: RECTANGULAR COORDINATES
EQUATIONS OF MOTION: RECTANGULAR COORDINATES Today s Objectives: Students will be able to: 1. Apply Newton s second law to determine forces and accelerations for particles in rectilinear motion. In-Class
More informationStudent AP Physics 1 Date. Newton s Laws B FR
Student AP Physics 1 Date Newton s Laws B FR #1 A block is at rest on a rough inclined plane and is connected to an object with the same mass as shown. The rope may be considered massless; and the pulley
More informationAP Physics First Nine Weeks Review
AP Physics First Nine Weeks Review 1. If F1 is the magnitude of the force exerted by the Earth on a satellite in orbit about the Earth and F2 is the magnitude of the force exerted by the satellite on the
More informationChapter 4 Dynamics: Newton s Laws of Motion
Chapter 4 Dynamics: Newton s Laws of Motion Force Newton s First Law of Motion Mass Newton s Second Law of Motion Newton s Third Law of Motion Weight the Force of Gravity; and the Normal Force Applications
More informationExample. F and W. Normal. F = 60cos 60 N = 30N. Block accelerates to the right. θ 1 F 1 F 2
Physic 3 Lecture 7 Newton s 3 d Law: When a body exerts a force on another, the second body exerts an equal oppositely directed force on the first body. Frictional forces: kinetic friction: fk = μk N static
More informationChapter 5 Newton s Laws of Motion. Copyright 2010 Pearson Education, Inc.
Chapter 5 Newton s Laws of Motion Force and Mass Units of Chapter 5 Newton s First Law of Motion Newton s Second Law of Motion Newton s Third Law of Motion The Vector Nature of Forces: Forces in Two Dimensions
More informationWhich, if any, of the velocity versus time graphs below represent the movement of the sliding box?
Review Packet Name: _ 1. A box is sliding to the right along a horizontal surface with a velocity of 2 m/s. There is friction between the box and the horizontal surface. The box is tied to a hanging stone
More informationO Which force produces the greatest torque about the point O (marked by the blue dot)?
Q10.1 The four forces shown all have the same magnitude: F 1 = F 2 = F 3 = F 4. F 1 F 3 O Which force produces the greatest torque about the point O (marked by the blue dot)? F 2 F 4 A. F 1 B. F 2 C. F
More informationIsaac Newton ( )
Isaac Newton (1642-1727) In the beginning of 1665 I found the rule for reducing any degree of binomial to a series. The same year in May I found the method of tangents and in November the method of fluxions
More informationPhysics 201 Lecture 16
Physics 01 Lecture 16 Agenda: l Review for exam Lecture 16 Newton s Laws Three blocks are connected on the table as shown. The table has a coefficient of kinetic friction of 0.350, the masses are m 1 =
More informationANSWER'SHEET' 'STAPLE'TO'FRONT'OF'EXAM'! Name:!!!CWID:!!! Lab'section'(circle'one):' 6!(W!3pm)! 8!(W!7pm)!!!
ANSWER'SHEET' 'STAPLE'TO'FRONT'OF'EXAM' Name: CWID: Lab'section'(circle'one):' 6(W3pm) 8(W7pm) Multiplechoice: 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. Shortanswer: 16. 17. 18. 19. 20. 5(R7pm)
More information